Question bank/NEET UG/Chemistry

NEET UGChemistryModerateRe-NEET 2026

The amount of carbon dioxide evolved upon complete combustion of 116 g of n-butane is
(Given: atomic mass in amu H = 1, C = 12 and O = 16)

Show answer and solution
Sol. C4H10+132O2→4CO2+5H2OC_4H_{10} + \frac{13}{2}O_2 \rightarrow 4CO_2 + 5H_2O
∴\therefore 1 mole C4H10C_4H_{10} produces 4 mole CO2CO_2
∴\therefore 58 g C4H10≡4×44C_4H_{10} \equiv 4 \times 44 g CO2CO_2
∴\therefore 116 g C4H10≡4×4458×116=352C_4H_{10} \equiv \frac{4 \times 44}{58} \times 116 = 352 g

Source: geekyrakshit/indian-exam-questions / reneet2026-code50

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