Question bank/NEET UG/Chemistry

NEET UGChemistryModerateRe-NEET 2026

The lanthanide ion having four unpaired electrons is
(Given : Atomic numbers of Ce = 58, Nd = 60, Tb = 65 and Ho = 67)

Show answer and solution
Sol. The outermost electronic configuration is
Ho3+^{3+} 4f10^{10} <image_1>
4 unpaired electrons
Nd3+^{3+} 4f3^{3} 3 unpaired electrons
Ce3+^{3+} 4f1^{1} 1 unpaired electron
Tb3+^{3+} 4f8^{8} <image_2>
6 unpaired electrons

Source: geekyrakshit/indian-exam-questions / reneet2026-code50

More NEET UG questionsChapter practice

Need a video for this idea?

Scan any doubt from your notes and get a whiteboard explanation.

Scan a doubtView plans