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Coordinate Geometry

JEE Main level, single correct, medium

1 of 5

Question 1 of 5

The equation of the tangent to the parabola $y^2 = 8x$ with slope $m = 2$ is:

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Answer: (D) $y = 2x + 1$

For

y^2 = 4ax

4a = 8 \implies a = 2

. Tangent with slope

m

y = mx + a/m = 2x + 2/2 = 2x + 1

JEE Main question paper PDF

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JEE Main 2025 Apr 2 Shift 1 question paper

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JEE Main Mathematics practice question on Coordinate Geometry, with the answer and a step-by-step solution. Scan a question from your own book or paper to get a whiteboard video.

The equation of the tangent to the parabola y2=8xy^2 = 8xy2=8x with slope m=2m = 2m=2 is:

JEE Main question paper PDF

More Mathematics practice

The equation of the tangent to the parabola $y^2 = 8x$ with slope $m = 2$ is: