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Electromagnetic Waves

JEE Main level, single correct, medium

1 of 165

Question 1 of 165

In an EM wave propagating in vacuum, the amplitude of electric field is $E_0 = 60\,\text{V/m}$ . The amplitude of magnetic field $B_0$ is:

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Answer: (A) $2 \times 10^{-7}\,\text{T}$

B_0 = \frac{E_0}{c} = \frac{60}{3 \times 10^8} = 2 \times 10^{-7}\,\text{T}

JEE Main question paper PDF

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JEE Main 2025 Apr 2 Shift 1 question paper

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JEE Main Physics practice question on Electromagnetic Waves, with the answer and a step-by-step solution. Scan a question from your own book or paper to get a whiteboard video.

In an EM wave propagating in vacuum, the amplitude of electric field is E0=60 V/mE_0 = 60\,\text{V/m}E0​=60V/m. The amplitude of magnetic field B0B_0B0​ is:

JEE Main question paper PDF

More Physics practice

In an EM wave propagating in vacuum, the amplitude of electric field is $E_0 = 60\,\text{V/m}$ . The amplitude of magnetic field $B_0$ is: