Modern Physics

Olympiad (NSEP) level, single correct, hard

3 of 5

Question 3 of 5

A particle of rest mass m0m_0 moves with speed v=0.8cv = 0.8c. The relativistic kinetic energy of the particle is equal to:

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Answer: (B) 23m0c2\frac{2}{3} m_0 c^2

γ=11−v2/c2=11−0.64=10.6=53\gamma = \frac{1}{\sqrt{1 - v^2/c^2}} = \frac{1}{\sqrt{1 - 0.64}} = \frac{1}{0.6} = \frac{5}{3}. Kinetic energy K=(γ−1)m0c2=(5/3−1)m0c2=23m0c2K = (\gamma - 1) m_0 c^2 = (5/3 - 1) m_0 c^2 = \frac{2}{3} m_0 c^2.
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