Question 34 of 180

The equivalent capacitance of the combination shown is

A$2C$B$\dfrac{5}{3}C$C$\dfrac{C}{2}$D$4C$

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Answer: (A) $2C$

The potential difference across the branches EF&GH is zero. So, the equivalent capacitance will be only due to the combination of two capacitors in parallel.
${C}_{eq}=C+C$
$\Rightarrow {C}_{eq}=2C$

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