Capacitors

JEE Main level, single correct, medium

41 of 180

Question 41 of 180

Calculate the amount of charge on capacitor of 4μF.4\mu F. The internal resistance of battery is 1Ω:1\Omega :

Show answer and solution

Answer: (B) 8μC8\mu C


Using
i=54+1=1Ai=\dfrac{5}{4+1}=1A
∴VAB=i×4=4V∴VAC=VCB=2∴{V}_{AB}=i\times 4=4V∴{V}_{AC}={V}_{CB}=2 Volt
∴q∴q on 4μF=CVAC=8μC4\mu F=C{V}_{AC}=8\mu C

JEE Main question paper PDF

Open a shift to read the full paper on this page, or download it.

JEE Main 2025 Apr 2 Shift 1 question paper

Open Download PDF

Opening paper…

Explain it as a whiteboard videoStep-by-step, in Hinglish or English. Your first video needs no login.Solved it on paper but got it wrong?Upload a photo of your working. Mistake Doctor marks the exact line that broke.
See it move: Capacitors, dielectrics and RC circuits simulationDrag the sliders and watch the numbers in this question change.

More Physics practice

JEE Main Physics practice question on Capacitors (Grouping of capacitors), with the answer and a step-by-step solution. Scan a question from your own book or paper to get a whiteboard video.