Question 65 of 180

Two capacitors ${C}_{1}$ and ${C}_{2}$ are charged to $\text{120 V}$ and $\text{200 V}$ respectively. It is found that by connecting them together the potential on each one can be made zero. Then:

A$3{C}_{1}+5{C}_{2}=0$B$9{C}_{1}=4{C}_{2}$C$5{C}_{1}=3{C}_{2}$D$3{C}_{1}=5{C}_{2}$

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Answer: (D) $3{C}_{1}=5{C}_{2}$

For potential to be made zero, after connection

$120{C}_{1}=200{C}_{2}$

$\Rightarrow 3{C}_{1}=5{C}_{2}$