Question 76 of 180

A bulb and a capacitor are connected in series across an ac supply. A dielectric is then placed between the plates of the capacitor. The glow of the bulb:

AincreasesBdecreasesCremains sameDbecomes zero

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Answer: (A) increases

$Z=\sqrt{R^2+X_C^2} \& X_C=\frac{1}{W C}$
due to dielectric
$\mathrm{C} \uparrow \Rightarrow \mathrm{X}_{\mathrm{C}} \downarrow \Rightarrow \mathrm{Z} \downarrow$
So, current increases $\&$ thus bulb will glow more brighter.

JEE Main Physics practice question on Capacitors (Capacitors with Dielectric), with the answer and a step-by-step solution. Scan a question from your own book or paper to get a whiteboard video.