Capacitors

JEE Main level, single correct, medium

97 of 180

Question 97 of 180

In the reported figure, a capacitor is formed by placing a compound dielectric between the plates of parallel plate capacitor. The expression for the capacity of the said capacitor will be: (Given the area of the plate =A=A )

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Answer: (A) 1534Kϵ0Ad\dfrac{15}{34}\dfrac{K{\epsilon }_{0}A}{d}

1Ceff=dK∈0A+2d3K∈0A+3d5∈0A\dfrac{1}{{C}_{eff}}=\dfrac{d}{K{\in }_{0}A}+\dfrac{2d}{3K{\in }_{0}A}+\dfrac{3d}{5{\in }_{0}A}
Ceff=15K∈0A34d{C}_{eff}=\dfrac{15K{\in }_{0}A}{34d}

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