Capacitors

JEE Main level, numerical answer, medium

126 of 180

Question 126 of 180

A time varying potential difference is applied between the plates of a parallel plate capacitor of capacitance 2.5μ F2.5 \mu \mathrm{~F}. The dielectric constant of the medium between the capacitor plates is 1 . It produces an instantaneous displacement current of 0.25 mA in the intervening space between the capacitor plates, the magnitude of the rate of change of the potential difference will be _____ Vs−1\mathrm{Vs}^{-1}.

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Answer: 100

CdVdt=IddVdt=IdC=0.25×10−32.5×10−6=100\begin{aligned} & \frac{\mathrm{CdV}}{\mathrm{dt}}=\mathrm{I}_{\mathrm{d}} \\ & \frac{\mathrm{dV}}{\mathrm{dt}}=\frac{\mathrm{I}_{\mathrm{d}}}{\mathrm{C}} \\ & =\frac{0.25 \times 10^{-3}}{2.5 \times 10^{-6}} \\ & =100\end{aligned}

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