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Electromagnetic Induction

JEE Main level, numerical answer, medium

9 of 153

Question 9 of 153

The magnetic flux $\phi$ (in weber) linked with a closed circuit of resistance $8\Omega$ varies with time (in seconds) as $\phi =5{t}^{2}-36t+1$ . The induced current in the circuit at $t=2s$ is _______ $A$ .

Show answer and solution

Answer: 2

Induced EMF is given by,

\left|\epsilon \right|=\left|-\left(\dfrac{d\phi }{dt}\right)\right|=\left|10t-36\right|

Now, it is given that at

t=2s,\epsilon =16V

.
Therefore,

i=\dfrac{\left|\epsilon \right|}{R}=\dfrac{16}{8}=2A

JEE Main question paper PDF

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JEE Main 2025 Apr 2 Shift 1 question paper

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JEE Main Physics practice question on Electromagnetic Induction (Magnetic Flux, Faraday's and Lenz law), with the answer and a step-by-step solution. Scan a question from your own book or paper to get a whiteboard video.

The magnetic flux ϕ\phiϕ (in weber) linked with a closed circuit of resistance 8Ω8\Omega8Ω varies with time (in seconds) as ϕ=5t2−36t+1\phi =5{t}^{2}-36t+1ϕ=5t2−36t+1. The induced current in the circuit at t=2st=2st=2s is _______ AAA.

JEE Main question paper PDF

More Physics practice

The magnetic flux $\phi$ (in weber) linked with a closed circuit of resistance $8\Omega$ varies with time (in seconds) as $\phi =5{t}^{2}-36t+1$ . The induced current in the circuit at $t=2s$ is _______ $A$ .