Electromagnetic Induction

JEE Main level, numerical answer, medium

30 of 153

Question 30 of 153

A coil of inductance 2H2H having negligible resistance is connected to a source of supply whose voltage is given by V=3tV=3t volt. (where tt is in second). If the voltage is applied when t=0t=0, then the energy stored in the coil after 4s4s in JJ,

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Answer: 144

ϵ=LdIdt\epsilon =\dfrac{LdI}{dt}
3∫04tdt=2∫01dI3{\int }_{0}^{4}tdt=2{\int }_{0}^{1}dI
32×16=2I\dfrac{3}{2}\times 16=2I
I=12I=12
V=12LI2=12×2(12)2=144JV=\dfrac{1}{2}L{I}^{2}=\dfrac{1}{2}\times 2{\left(12\right)}^{2}=144J

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