Electromagnetic Induction

JEE Main level, numerical answer, medium

34 of 153

Question 34 of 153

A circular coil of radius 10cm10cm is placed in a uniform magnetic field of 3.0×10−5T3.0\times {10}^{-5}T with its plane perpendicular to the field initially. It is rotated at constant angular speed about an axis along the diameter of coil and perpendicular to magnetic field so that it undergoes half of rotation in 0.2s0.2s. The maximum value of EMF induced (in μV\mu V) in the coil will be close to the integer....

Show answer and solution

Answer: 15

Flux as a function of time ϕ=B⃗⋅A⃗=ABcos⁡(ωt)\phi =\vec{B}\cdot \vec{A}=AB\cos (\omega t)
Emf induced,

e=−dϕdt=ABωsin⁡(ωt)e=\dfrac{-d\phi }{dt}=AB\omega \sin (\omega t)
Max. value of Emf
=ABω=AB\omega
=πR2Bω=\pi {R}^{2}B\omega
=3.14×0.1×0.1×3×10−5×π0.2=15=3.14\times 0.1\times 0.1\times 3\times {10}^{-5}\times \dfrac{\pi }{0.2}=15

JEE Main question paper PDF

Open a shift to read the full paper on this page, or download it.

JEE Main 2025 Apr 2 Shift 1 question paper

Open Download PDF

Opening paper…

Explain it as a whiteboard videoStep-by-step, in Hinglish or English. Your first video needs no login.Solved it on paper but got it wrong?Upload a photo of your working. Mistake Doctor marks the exact line that broke.
See it move: Electromagnetic induction simulationDrag the sliders and watch the numbers in this question change.

More Physics practice

JEE Main Physics practice question on Electromagnetic Induction (Magnetic Flux, Faraday's and Lenz law), with the answer and a step-by-step solution. Scan a question from your own book or paper to get a whiteboard video.