Question 37 of 153

A loop $ABCDEFA$ of straight edges has six corner points $A\left(0,0,0\right),B\left(5,0,0\right),C\left(5,5,0\right),D\left(0,5,0\right),E\left(0,5,5\right)$ and $F\left(0,0,5\right)$ . The magnetic field in this region is $\vec{B}=\left(3\hat{i}+4\hat{k}\right)T$ . The quantity of flux through the loop $ABCDEFA$ (in $Wb$ ) is _____________

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Answer: 175

$\phi =\vec{B}.\vec{A}=\left(3\hat{i}+4\hat{k}\right).\left(25\hat{i}+25\hat{k}\right)$

$\phi =\left(2\times 25\right)+\left(4\times 25\right)=175weber$