Electromagnetic Induction

JEE Main level, single correct, medium

45 of 153

Question 45 of 153

The flux linked with a coil at any instant ' tt ' is given by
ϕ=10t2−50t+250\phi=10 t^2-50 t+250
The induced emf at
t=3 st=3 \mathrm{~s} is

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Answer: (C) −10 V-10 \mathrm{~V}

e=−dϕdt=−(20t−50)=−10e=-\frac{d \phi}{d t}=-(20 t-50)=-10 volt

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