Electromagnetic Induction

JEE Main level, numerical answer, medium

53 of 153

Question 53 of 153

In an ac generator, a rectangular coil of 100100 turns each having area 14×10–2m214\times {10}^{–2}{m}^{2} is rotated at 360revmin⁡−1360rev{\min }^{-1} about an axis perpendicular to a uniform magnetic field of magnitude 3.0T3.0T. The maximum value of the emf produced will be ______ VV.
[Take π=227\pi =\dfrac{22}{7}]

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Answer: 1584

Maximum value of induced EMF can be written as,
ξmax⁡=NABω{\xi }_{\max }=NAB\omega
=100×(14×10−2)×3×(360×2π60)=100\times \left(14\times {10}^{-2}\right)\times 3\times \left(\dfrac{360\times 2\pi }{60}\right)
=1584V=1584V

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