Electromagnetic Induction

JEE Main level, single correct, medium

58 of 153

Question 58 of 153

In a coil of resistance 100Ω100\Omega, a current is induced by changing the magnetic flux through it as shown in the figure. The magnitude of change in flux through the coil is:

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Answer: (D) 250Wb250Wb

Emf=iR⇒−dϕdt=iREmf=iR\Rightarrow -\dfrac{d\phi }{dt}=iR

∫(−dϕ)=∫(idt)R\int \left(-d\phi \right)=\int (idt)R

q=ΔϕR=Area underi−tgraphq=\dfrac{\Delta \phi }{R}=\text{Area under}i-t\text{graph}

⇒∆ϕ=(12×10×0.5)×100=250Wb\Rightarrow ∆\phi =\left(\dfrac{1}{2}\times 10\times 0.5\right)\times 100=250Wb

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