Electromagnetic Induction

JEE Main level, single correct, medium

87 of 153

Question 87 of 153

An emf of 0.08V0.08V is induced in a metal rod of length 10cm10cm held normal to a uniform magnetic field of 0.4T0.4T, when move with a velocity of:

Show answer and solution

Answer: (D) 2ms−12m{s}^{-1}

The formula to calculate the motional emf induced in a moving conductor in a magnetic field is given by
ϵ=Blv...(1)\epsilon =Blv...\left(1\right)
Substitute the values of the known parameters into equation (1) and solve to calculate the required velocity of the rod.
0.08V=0.4T×(10cm×1m100cm)×v⇒v=0.08V0.4T×10cm×1m100cm=2ms−1\begin{matrix}0.08V & = & 0.4T\times \left(10cm\times \dfrac{1m}{100cm}\right)\times v \\ & \Rightarrow & v=\dfrac{0.08V}{0.4T\times 10cm\times \dfrac{1m}{100cm}} \\ & = & 2m{s}^{-1}\end{matrix}

JEE Main question paper PDF

Open a shift to read the full paper on this page, or download it.

JEE Main 2025 Apr 2 Shift 1 question paper

Open Download PDF

Opening paper…

Explain it as a whiteboard videoStep-by-step, in Hinglish or English. Your first video needs no login.Solved it on paper but got it wrong?Upload a photo of your working. Mistake Doctor marks the exact line that broke.
See it move: Electromagnetic induction simulationDrag the sliders and watch the numbers in this question change.

More Physics practice

JEE Main Physics practice question on Electromagnetic Induction (Motional and Rotational EMF), with the answer and a step-by-step solution. Scan a question from your own book or paper to get a whiteboard video.