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Electromagnetic Induction

JEE Main level, single correct, medium

101 of 153

Question 101 of 153

A metal conductor of length $1 \mathrm{~m}$ rotates vertically about one of its ends at angular velocity 5 radians per second. If the horizontal component of earth's magnetic field is $0.3 \times 10^{-4} \mathrm{~T}$ , then the e.m.f. developed between the two ends of the conductor is

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Answer: (B) depends on the intensity of the radiation

emf. developed is given by

\varepsilon_{\text {ind }}=\frac{1}{2} \mathrm{~B} \omega \mathrm{R}^2=50 \mu \mathrm{V} \text {. }

JEE Main question paper PDF

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JEE Main 2025 Apr 2 Shift 1 question paper

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JEE Main Physics practice question on Electromagnetic Induction (Motional and Rotational EMF), with the answer and a step-by-step solution. Scan a question from your own book or paper to get a whiteboard video.