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Electromagnetic Induction

JEE Main level, single correct, medium

107 of 153

Question 107 of 153

For the plane electromagnetic wave given by $E={E}_{0}\sin (\omega t–kx)$ and $B={B}_{0}\sin (\omega t-kx),$ the ratio of average electric energy density to average magnetic energy density is

Show answer and solution

Answer: (D) $1$

The formula to calculate the average electric energy density is given by

{U}_{E}=\dfrac{1}{2}{\epsilon }_{0}{E}^{2}...(1)

and, the formula to calculate average magnetic energy density is given by

{U}_{B}=\dfrac{1}{2{\mu }_{0}}{B}^{2}...(2)

For any particular electromagnetic wave, both magnetic and electric field are equally involved in contributing to energy density. Hence, the ratio of average electric energy density to magnetic energy density is

1

JEE Main question paper PDF

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JEE Main 2025 Apr 2 Shift 1 question paper

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More Physics practice

JEE Main Physics practice question on Electromagnetic Induction (Inductance), with the answer and a step-by-step solution. Scan a question from your own book or paper to get a whiteboard video.

For the plane electromagnetic wave given by E=E0sin⁡(ωt–kx)E={E}_{0}\sin (\omega t–kx)E=E0​sin(ωt–kx) and B=B0sin⁡(ωt−kx),B={B}_{0}\sin (\omega t-kx),B=B0​sin(ωt−kx), the ratio of average electric energy density to average magnetic energy density is

JEE Main question paper PDF

More Physics practice

For the plane electromagnetic wave given by $E={E}_{0}\sin (\omega t–kx)$ and $B={B}_{0}\sin (\omega t-kx),$ the ratio of average electric energy density to average magnetic energy density is