Electromagnetic Induction

JEE Main level, single correct, medium

113 of 153

Question 113 of 153

In the circuit shown below, the key K\mathrm{K} is closed at t=0\mathrm{t}=0. The current through the battery is

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Answer: (B) VR2\frac{V}{R_2} at t=0t=0 and V(R1+R2)R1R2\frac{V\left(R_1+R_2\right)}{R_1 R_2} at t=∞t=\infty

At t=0\mathrm{t}=0, inductor behaves like an infinite resistance
So at t=0,i=VR2t=0, i=\frac{V}{R_2} and at t=∞t=\infty, inductor behaves like a conducting wire
i=VReq =V(R1+R2)R1R2\mathrm{i}=\frac{\mathrm{V}}{\mathrm{R}_{\text {eq }}}=\frac{\mathrm{V}\left(\mathrm{R}_1+\mathrm{R}_2\right)}{\mathrm{R}_1 \mathrm{R}_2}

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