Electromagnetic Induction

JEE Main level, numerical answer, medium

121 of 153

Question 121 of 153

When a coil is connected across a 20 V20 \mathrm{~V} dc supply, it draws a current of 5 A5 \mathrm{~A}. When it is connected across 20 V,50 Hz20 \mathrm{~V}, 50 \mathrm{~Hz} ac supply, it draws a current of 4 A4 \mathrm{~A}. The self inductance of the coil is ______ mH\mathrm{mH}. (( Take π=3\pi=3 )

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Answer: 10

Case-I:

i=20R⇒R=4Ωi=\frac{20}{R} \Rightarrow R=4 \Omega
Case-II:

i=20Z4=20R2+XL2⇒R2+XL2=5R2+XL2=25⇒XL=3ΩL=32πf=12×50=1000100mHL=10mH\begin{aligned} & \mathrm{i}=\frac{20}{\mathrm{Z}} \\ & 4=\frac{20}{\sqrt{\mathrm{R}^2+\mathrm{X}_{\mathrm{L}}^2}} \Rightarrow \sqrt{\mathrm{R}^2+\mathrm{X}_{\mathrm{L}}^2}=5 \\ & \mathrm{R}^2+\mathrm{X}_{\mathrm{L}}^2=25 \Rightarrow \mathrm{X}_{\mathrm{L}}=3 \Omega \\ & \mathrm{L}=\frac{3}{2 \pi \mathrm{f}}=\frac{1}{2 \times 50}=\frac{1000}{100} \mathrm{mH} \\ & \mathrm{L}=10 \mathrm{mH}\end{aligned}

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