Electromagnetic Induction

JEE Main level, single correct, medium

124 of 153

Question 124 of 153

Two conducting circular loops A and B are placed in the same plane with their centers coinciding as shown in figure. The mutual inductance between them is :

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Answer: (D) μ0πa22b\frac{\mu_0 \pi a^2}{2 b}

ϕ=Mi=BA⇒Mi=μ0i2 bπa2∴M=μ0πa22 b\begin{aligned} & \phi=\mathrm{Mi}=\mathrm{BA} \\ & \Rightarrow \mathrm{Mi}=\frac{\mu_0 \mathrm{i}}{2 \mathrm{~b}} \pi \mathrm{a}^2 \\ & \therefore \mathrm{M}=\frac{\mu_0 \pi \mathrm{a}^2}{2 \mathrm{~b}}\end{aligned}

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