Electromagnetic Induction

JEE Main level, numerical answer, medium

133 of 153

Question 133 of 153

In a fluorescent lamp choke (a small transformer) 100V100V of reverse voltage is produced when the choke current changes uniformly from 0.25A0.25A to 00 in a duration of 0.025ms0.025ms . The self-inductance of the choke (in mHmH ) is estimated to be ________

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Answer: 10

100=L(0.25)0.025×103100=\dfrac{L\left(0.25\right)}{0.025}\times {10}^{3}
∴L=100×10−4H∴L=100\times {10}^{-4}H
=10mH=10mH

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