Electromagnetic Induction

JEE Main level, numerical answer, medium

146 of 153

Question 146 of 153



In the given circuit the sliding contact is pulled outwards such that electric current in the circuit changes at the rate of 8 A/s8 \mathrm{~A} / \mathrm{s}. At an instant when R is 12Ω12 \Omega, the value of the current in the circuit will be ______ A.

Show answer and solution

Answer: 3

ε−LdIdt−IR=012−3×(−8)−I×12=0I=3\begin{aligned} & \varepsilon-\frac{\mathrm{LdI}}{\mathrm{dt}}-\mathrm{IR}=0 \\ & 12-3 \times(-8)-\mathrm{I} \times 12=0 \\ & \mathrm{I}=3\end{aligned}

JEE Main question paper PDF

Open a shift to read the full paper on this page, or download it.

JEE Main 2025 Apr 2 Shift 1 question paper

Open Download PDF

Opening paper…

Explain it as a whiteboard videoStep-by-step, in Hinglish or English. Your first video needs no login.Solved it on paper but got it wrong?Upload a photo of your working. Mistake Doctor marks the exact line that broke.
See it move: Electromagnetic induction simulationDrag the sliders and watch the numbers in this question change.

More Physics practice

JEE Main Physics practice question on Electromagnetic Induction (LR Circuit), with the answer and a step-by-step solution. Scan a question from your own book or paper to get a whiteboard video.