Question 8 of 276

A current of $1.5A$ is flowing through a triangle, of side $9cm$ each. The magnetic field at the centroid of the triangle is :
(Assume that the current is flowing in the clockwise direction.)

A$2\sqrt{3}\times {10}^{-5}T,$ inside the plane of triangleB$2\sqrt{3}\times {10}^{-7}T,$ outside the plane of triangleC$3\times {10}^{-7}T,$ outside the plane of triangleD$3\times {10}^{-5}T,$ inside the plane of triangle

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Answer: (D) $3\times {10}^{-5}T,$ inside the plane of triangle

${B}_{1}=\dfrac{{\mu }_{0}I}{4\pi R}\left(2\sin 60\right)=\dfrac{4\pi \times {10}^{-7}\times 1.5}{4\pi .\left(\dfrac{3\sqrt{3}}{2}\right)\times {10}^{-2}}\times 2\times \dfrac{\sqrt{3}}{2}=1\times {10}^{-5}$
${B}_{net}=3{B}_{1}=3\times {10}^{-5}T⊗$

JEE Main Physics practice question on Magnetic Effects & Magnetism (Biot-Savart's Law and Ampere's Circuital Law), with the answer and a step-by-step solution. Scan a question from your own book or paper to get a whiteboard video.