Question 11 of 276

A current loop, having two circular arcs joined by two radial lines is shown in the figure. It carries a current of $10A.$ The magnetic field at point $O$ will be close to:

A$1.5\times {10}^{-7}T$B$1.0\times {10}^{-7}T$C$1.5\times {10}^{-5}T$D$1.0\times {10}^{-5}T$

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Answer: (D) $1.0\times {10}^{-5}T$

Magnetic field due to $PQ$ and $RS$ are zero at ' $O$ '.

Magnetic field due to $QR$

${B}_{QR}=\dfrac{{\mu }_{0}}{4\pi }\dfrac{10}{3\times {10}^{-2}}\dfrac{\pi }{4}$ (outwards)

Magnetic field due to $SP$

${B}_{SP}=\dfrac{{\mu }_{0}}{4\pi }\dfrac{10}{5\times {10}^{-2}}\dfrac{\pi }{4}$ (inwards)

Net field $B=\dfrac{{\mu }_{o}}{4\pi }\dfrac{10\pi }{4\times {10}^{-2}}\left(\dfrac{1}{3}-\dfrac{1}{5}\right)$

$=1.0\times {10}^{-5}T$

JEE Main Physics practice question on Magnetic Effects & Magnetism (Biot-Savart's Law and Ampere's Circuital Law), with the answer and a step-by-step solution. Scan a question from your own book or paper to get a whiteboard video.