Magnetic Effects & Magnetism

JEE Main level, numerical answer, medium

24 of 276

Question 24 of 276

A loop ABCDA , carrying current I=12 A\mathrm{I}=12 \mathrm{~A}, is placed in a plane, consists of two semi-circular segments of radius R1=6π mR_1=6 \pi \mathrm{~m} and R2=4π m\mathrm{R}_2=4 \pi \mathrm{~m}. The magnitude of the resultant magnetic field at center O is k×10−7 T\mathrm{k} \times 10^{-7} \mathrm{~T}. The value of k is ______ (Given μ0=4π×10−7TmA−1\mu_0=4 \pi \times 10^{-7} \mathrm{Tm} \mathrm{A}^{-1})

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Answer: 1

Magnetic field due to AB&CD=0\mathrm{AB} \& \mathrm{CD}=0
$\begin{aligned}

& \mathrm{B}_0=\left|\mathrm{B}_{\mathrm{R}_1}-\mathrm{B}_{\mathrm{R}_2}\right| \\

& =\frac{\mu_0 \mathrm{I}}{4 \mathrm{R}_2}-\frac{\mu_0 \mathrm{I}}{4 \mathrm{R}_1} \\

& =\frac{4 \pi \times 10^{-7} \times 12}{4}\left(\frac{1}{4 \pi}-\frac{1}{6 \pi}\right) \\

& =12 \pi \times 10^{-7}\left(\frac{1}{12 \pi}\right) \\

& =1 \times 10^{-7}

\end{aligned}$

K=1K=1

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