Magnetic Effects & Magnetism

JEE Main level, single correct, medium

42 of 276

Question 42 of 276

A long straight wire of circular cross-section (radius aa) is carrying steady current I.I. The current II is uniformly distributed across this cross-section. The magnetic field is

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Answer: (B) directly proportional to rr in the region r<ar\lt a and inversely proportional to rr in the region r>ar\gt a

The formula to calculate the magnetic field inside the conducting wire is given by
Bin=μ0Jr2...(1){B}_{\text{in}}=\dfrac{{\mu }_{0}Jr}{2}...(1)
The formula to calculate the magnetic field outside the conducting wire is given by

Bout=μ0Ja22r...(2){B}_{\text{out}}=\dfrac{{\mu }_{0}J{a}^{2}}{2r}...(2)
From equation (1), it can be concluded that the magnetic field is directly proportional to the radial distance inside the wire, whereas from equation (2), it can be concluded that the magnetic field is inversely proportional to the radial distance outside the wire.

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