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Magnetic Effects & Magnetism

JEE Main level, single correct, medium

168 of 276

Question 168 of 276

A particle of charge $16 \times 10^{-16} \mathrm{C}$ moving with velocity $10 \mathrm{~ms}^{-1}$ along $x$ -axis enters a region where magnetic field of induction
$\vec{B}$ is along the $y$ -axis and an electric field of magnitude $10^4 \mathrm{Vm}^{-1}$ is along the negative $z$ -axis.
If the charged particle continues moving along $x$ -axis, the magnitude of $\vec{B}$ is :

Show answer and solution

Answer: (C) $1 \times 10^3 \mathrm{~Wb} \mathrm{~m}^{-2}$

Since particle is moving undeflected
So,

q_E=q v B

\Rightarrow B=\frac{E}{V}=\frac{10^4}{10}=10^3 \mathrm{wb} / \mathrm{m}^2

JEE Main question paper PDF

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JEE Main 2025 Apr 2 Shift 1 question paper

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