Magnetic Effects & Magnetism

JEE Main level, single correct, medium

177 of 276

Question 177 of 276

A charged particle of mass m\mathrm{m} and charge qq travels on a circular path of radius rr that is perpendicular to a magnetic field B\mathrm{B}. The time taken by the particle to complete one revolution is

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Answer: (D) 2πmqB\frac{2 \pi m}{q B}

mω2r=Bqωr\mathrm{m} \omega^2 \mathrm{r}=\mathrm{Bq} \omega \mathrm{r}
ω=Bq/m\omega=\mathrm{Bq} / \mathrm{m}
T=2πmqB\mathrm{T}=\frac{2 \pi \mathrm{m}}{\mathrm{qB}}

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