Magnetic Effects & Magnetism

JEE Main level, numerical answer, medium

190 of 276

Question 190 of 276

Two long parallel wires XX and YY, separated by a distance of 6 cm , carry currents of 5A and 4A, respectively, in opposite directions as shown in the figure. Magnitude of the resultant magnetic field at point P at a distance of 4 cm from wire Y is x×10−5 Tx \times 10^{-5} \mathrm{~T}. The value of xx is__________ . Take permeability of free space as μ0=4π×10−7SI\mu_0=4 \pi \times 10^{-7} \mathrm{SI} units.

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Answer: 1



B=μ0(5)2π×.01−μ042π×0.04=−100μ04π=−100×10−7=−1×10−5 T\begin{aligned} & B=\frac{\mu_0(5)}{2 \pi \times .01}-\frac{\mu_0 4}{2 \pi \times 0.04} \\ & =-\frac{100 \mu_0}{4 \pi} \\ & =-100 \times 10^{-7} \\ & =-1 \times 10^{-5} \mathrm{~T}\end{aligned}

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