Magnetic Effects & Magnetism

JEE Main level, single correct, medium

217 of 276

Question 217 of 276

A square loop of side 2a,2a, and carrying current II is kept in XZXZ plane with its centre at origin. A long wire carrying the same current II is placed parallel to the zz-axis and passing through the point (0,b,0),(b>>a)(0,b,0),(b\gt \gt a). The magnitude of the torque on the loop about zz-axis is given by.

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Answer: (C) 2μ0Ia22πb\dfrac{2{\mu }_{0}Ia22}{\pi b}


Net force acting on wire
ABAB & CDCD are zero

F1=ILB=I×(2a)×(μ0I2πa2+b2)=μ0I2aπa2+b2{F}_{1}=ILB=I\times \left(2a\right)\times \left(\dfrac{{\mu }_{0}I}{2\pi \sqrt{{a}^{2}+{b}^{2}}}\right)=\dfrac{{\mu }_{0}{I}^{2}a}{\pi \sqrt{{a}^{2}+{b}^{2}}}
τ=F1cosθ×2a=μ0I2aπa2+b2×ba2+b2×2a\tau ={F}_{1}cos\theta \times 2a=\dfrac{{\mu }_{0}{I}^{2}a}{\pi \sqrt{{a}^{2}+{b}^{2}}}\times \dfrac{b}{\sqrt{{a}^{2}+{b}^{2}}}\times 2a
τ=2μ0I2a2bπ(a2+b2)≈2μ0I2a2πb,(a≪b)\tau =\dfrac{2{\mu }_{0}{I}^{2}{a}^{2}b}{\pi \left({a}^{2}+{b}^{2}\right)}\approx \dfrac{2{\mu }_{0}{I}^{2}{a}^{2}}{\pi b},\left(a≪b\right)

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