Magnetic Effects & Magnetism

JEE Main level, single correct, medium

225 of 276

Question 225 of 276

A rigid square loop of side ‘a’‘a’ and carrying current I2{I}_{2} is lying on a horizontal surface near a long current I1{I}_{1} carrying wire in the same plane as shown in figure. The net force on the loop due to the wire will be:

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Answer: (B) Repulsive and equal to μ0I1I24π\dfrac{{\mu }_{0}{I}_{1}{I}_{2}}{4\pi }


Force on segment 1-2 and 3-4 will get cancel out.

Force on segment 4-1,

F1=μ0I1I22πa×a{F}_{1}=\dfrac{{\mu }_{0}{I}_{1}{I}_{2}}{2\pi a}\times a toward Right
Force on segment 2-3:

F2=μ0I1I22π(2a)×a{F}_{2}=\dfrac{{\mu }_{0}{I}_{1}{I}_{2}}{2\pi (2a)}\times a toward left
Net force on loop:

Fnet=F1−F2{F}_{net}={F}_{1}-{F}_{2} toward Right
=μ0I1I22π−μ0I1I24π=\dfrac{{\mu }_{0}{I}_{1}{I}_{2}}{2\pi }-\dfrac{{\mu }_{0}{I}_{1}{I}_{2}}{4\pi }
=μ0I1I24π=\dfrac{{\mu }_{0}{I}_{1}{I}_{2}}{4\pi } toward Right or repulsive

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