Question 247 of 276

A wire of length $314cm$ carrying current of $14A$ is bent to form a circle. The magnetic moment of the coil is $A-{m}^{2}$. [Given $\pi =3.14$]

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Answer: 11

Length of the wire $l$ when bent becomes circumference of the loop, whose radius is given by $R=\dfrac{l}{2\pi }=\dfrac{314}{100\left(2\times 3.14\right)}=\dfrac{1}{2}m$
Magnetic moment of the coil is $M=IA$
$=14\times \pi {R}^{2}$
$=14\times \left(3.14\right)\times \dfrac{1}{4}$
$=10.99\approx 11.00A-{m}^{2}$

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