Question 5 of 121

The resultant of two vectors $\vec{A}$ and $\vec{B}$ is perpendicular to $\vec{A}$ and its magnitude is half that of $\vec{B}$. The angle between vectors $\vec{A}$ and $\vec{B}$ is ______ $\circ$.

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Answer: 150

$\begin{aligned}& \mathrm{B} \cos \theta=\frac{\mathrm{B}}{2} \\
& \Rightarrow \theta=60^{\circ}\end{aligned}$
So, angle between $\overrightarrow{\mathrm{A}} \& \overrightarrow{\mathrm{B}}$ is $90^{\circ}+60^{\circ}=150^{\circ}$

JEE Main Physics practice question on Mathematics in Physics (Addition and Subtraction of Vectors), with the answer and a step-by-step solution. Scan a question from your own book or paper to get a whiteboard video.