Fluid Mechanics

JEE Main level, single correct, medium

96 of 192

Question 96 of 192

Two liquids A and B have θA\theta_{\mathrm{A}} and θB\theta_{\mathrm{B}} as contact angles in a capillary tube. If K=cos⁡θA/cos⁡θBK=\cos \theta_A / \cos \theta_B. then identify the correct statement:

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Answer: (C) K is negative, then liquid A has concave meniscus and liquid BB has convex meniscus

k=cos⁡θAcos⁡θB\mathrm{k}=\frac{\cos \theta_{\mathrm{A}}}{\cos \theta_{\mathrm{B}}}
It is negative when cos⁡θA&cos⁡θB\cos \theta_A \& \cos \theta_B are of opposite sign. so option (3)

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