Fluid Mechanics

JEE Main level, single correct, medium

104 of 192

Question 104 of 192

The excess pressure inside a soap bubble is thrice the excess pressure inside a second soap bubble. The ratio between the volume of the first and the second bubble is:

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Answer: (C) 1:271: 27


P1−P0=4 Tr1P2−P0=4 Tr2\mathrm{P}_1-\mathrm{P}_0=\frac{4 \mathrm{~T}}{\mathrm{r}_1} \qquad \quad \quad \quad\mathrm{P}_2-\mathrm{P}_0=\frac{4 \mathrm{~T}}{\mathrm{r}_2}
P1−P0=3(P2−P0)4 Tr1=34 Tr2r2=3r1V1 V2=43πr1343πr23=127\begin{aligned} & \mathrm{P}_1-\mathrm{P}_0=3\left(\mathrm{P}_2-\mathrm{P}_0\right) \\ & \frac{4 \mathrm{~T}}{\mathrm{r}_1}=3 \frac{4 \mathrm{~T}}{\mathrm{r}_2} \\ & \mathrm{r}_2=3 \mathrm{r}_1 \\ & \frac{\mathrm{V}_1}{\mathrm{~V}_2}=\frac{\frac{4}{3} \pi \mathrm{r}_1^3}{\frac{4}{3} \pi \mathrm{r}_2^3}=\frac{1}{27}\end{aligned}

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