प्रश्न 8. अभिक्रिया 2Ce⁴⁺ + Co → 2Ce³⁺ + Co²⁺ के लिए 4+/Ce³⁺ का मान ज्ञात कीजिए।

Step-by-step solution

1. 1

   Given reaction and potentials

   Overall reaction: $2\text{Ce}^{4+} + \text{Co} \rightarrow 2\text{Ce}^{3+} + \text{Co}^{2+}$
2. 2

   Given standard potentials

   Given: $\text{E}^{\circ}_{\text{cell}} = 0.46 \text{ V}$ and $\text{E}^{\circ}_{\text{Co}^{2+}/\text{Co}} = -0.28 \text{ V}$
3. 3

   Cell potential formula

   Standard cell potential: $\text{E}^{\circ}_{\text{cell}} = \text{E}^{\circ}_{\text{cathode}} - \text{E}^{\circ}_{\text{anode}}$

   $$\text{E}^{\circ}_{\text{cell}} = \text{E}^{\circ}_{\text{cathode}} - \text{E}^{\circ}_{\text{anode}}$$
4. 4

   Identify cathode and anode

   In the given reaction, $\text{Ce}^{4+}$ is reduced to $\text{Ce}^{3+}$ (cathode), and $\text{Co}$ is oxidized to $\text{Co}^{2+}$ (anode).
5. 5

   Substitute values

   Substitute the known values into the formula:

   $$0.46 = \text{E}^{\circ}_{\text{Ce}^{4+}/\text{Ce}^{3+}} - (-0.28)$$
6. 6

   Simplify the equation

   Simplify the equation to solve for $\text{E}^{\circ}_{\text{Ce}^{4+}/\text{Ce}^{3+}}$:

   $$0.46 = \text{E}^{\circ}_{\text{Ce}^{4+}/\text{Ce}^{3+}} + 0.28$$
7. 7

   Solve for unknown potential

   Isolate $\text{E}^{\circ}_{\text{Ce}^{4+}/\text{Ce}^{3+}}$:

   $$\text{E}^{\circ}_{\text{Ce}^{4+}/\text{Ce}^{3+}} = 0.46 - 0.28$$
8. 8

   Final Answer

   The standard reduction potential for $\text{Ce}^{4+}/\text{Ce}^{3+}$ is:

   $$\text{E}^{\circ}_{\text{Ce}^{4+}/\text{Ce}^{3+}} = 0.18 \text{ V}$$