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Stoichiometry Solver

Balance the reaction, then convert grams or moles of one substance into another with the mole ratio shown step by step. Free stoichiometry solver for GCSE, AP Chemistry and JEE/NEET.

Answer

m(H2O)=35.74 gm(\mathrm{H_{2}O}) = 35.74\ \mathrm{g}

35.74 g of H2O (1.984 mol)

  1. 1

    Balance the equation

    The equation as entered is already balanced.

    2 H2+O2→2 H2O2\,\mathrm{H_{2}} + \mathrm{O_{2}} \rightarrow 2\,\mathrm{H_{2}O}
  2. 2

    Molar mass of H2

    M(H2)=2(1.008)=2.016 g/molM(\mathrm{H_{2}}) = 2(1.008) = 2.016\ \mathrm{g/mol}
  3. 3

    Convert grams to moles

    n(H2)=4 g2.016 g/mol=1.984 moln(\mathrm{H_{2}}) = \frac{4\ \mathrm{g}}{2.016\ \mathrm{g/mol}} = 1.984\ \mathrm{mol}
  4. 4

    Mole ratio from the coefficients

    From the balanced equation, 2 mol H2 corresponds to 2 mol H2O.

    n(H2O)n(H2)=22\frac{n(\mathrm{H_{2}O})}{n(\mathrm{H_{2}})} = \frac{2}{2}
  5. 5

    Moles of H2O

    n(H2O)=1.984 mol×22=1.984 moln(\mathrm{H_{2}O}) = 1.984\ \mathrm{mol} \times \frac{2}{2} = 1.984\ \mathrm{mol}
  6. 6

    Convert moles of H2O to grams

    M(H2O) = 18.015 g/mol.

    m(H2O)=1.984 mol×18.015 g/mol=35.74 gm(\mathrm{H_{2}O}) = 1.984\ \mathrm{mol} \times 18.015\ \mathrm{g/mol} = 35.74\ \mathrm{g}

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FAQ

What is the stoichiometry roadmap?

grams A → moles A (÷ molar mass) → moles B (× mole ratio) → grams B (× molar mass).

Does it balance the equation first?

Yes — the mole ratio always comes from the balanced equation.

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