Example 1
A solid sphere rolls without slipping down an incline from rest, dropping a height of 1.4 m. Find its speed at the bottom (g = 9.8 m/s²).
- 1For a solid sphere, .
- 2Energy conservation: .
- 3So .
Physics · JEE Main · JEE Advanced · NEET
Rotational motion is the chapter most students find hardest in mechanics, and it is also one of the most tested. Most papers include a question on rolling, moment of inertia or angular momentum conservation.
The good news: nearly every question reduces to three tools — τ = Iα about the right axis, conservation of angular momentum when external torque is zero, and energy conservation for rolling. Pick the right tool first and the algebra is short.
Standard results for ring, disc, rod, sphere, plus the parallel- and perpendicular-axis theorems.
Choose the axis carefully — about the contact point or the centre of mass for rolling bodies.
Conserved when net external torque about the axis is zero: a person on a turntable, a lump sticking to a disc.
v = ωR at the contact point; kinetic energy splits into translation and rotation.
Acceleration g sinθ / (1 + k²/R²) — the body with the smaller k²/R² reaches the bottom first.
Torque
Angular momentum
Parallel axis theorem
Rolling kinetic energy
Speed at bottom of incline
Common k²/R²
Patterns that repeat across previous-year JEE and NEET papers for this chapter.
Example 1
Example 2
The one with the smallest k²/R²: solid sphere (2/5), then disc (1/2), then hollow sphere (2/3), then ring (1). Mass and radius do not matter.
When the net external torque about the chosen axis is zero — internal forces such as clay sticking or a person walking on a turntable do not change it.
Yes. NEET usually tests moment of inertia, torque and rolling with direct formula-based questions, while JEE Advanced adds multi-concept problems.
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