Alternating Current

JEE Main level, single correct, medium

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Question 1 of 190

In a series LCR circuit with L=10 mHL = 10\,\text{mH}, C=1 μFC = 1\,\mu\text{F}, the resonant angular frequency ω0\omega_0 is:

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Answer: (C) 104 rad/s10^4\,\text{rad/s}

ω0=1LC=110×10−3×10−6=110−8=104 rad/s\omega_0 = \frac{1}{\sqrt{LC}} = \frac{1}{\sqrt{10 \times 10^{-3} \times 10^{-6}}} = \frac{1}{\sqrt{10^{-8}}} = 10^4\,\text{rad/s}.

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