Atoms & Nuclei

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Question 1 of 239

The energy of an electron in the ground state of hydrogen atom is −13.6 eV-13.6\,\text{eV}. In the first excited state (n=2n=2), its energy is:

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Answer: (A) −3.4 eV-3.4\,\text{eV}

En=−13.6/n2 eVE_n = -13.6/n^2\,\text{eV}. For n=2n=2, E2=−13.6/4=−3.4 eVE_2 = -13.6/4 = -3.4\,\text{eV}.

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