Chemical Kinetics

JEE Main level, single correct, medium

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Question 1 of 4

For a first order reaction, the time required for 99.9%99.9\% completion is related to its half-life t1/2t_{1/2} by:

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Answer: (A) t99.9%=10t1/2t_{99.9\%} = 10 t_{1/2}

t99.9%=2.303klog⁡(1000.1)=2.303k×3=3×2.303×0.3010k×0.3010≈10t1/2t_{99.9\%} = \frac{2.303}{k} \log\left(\frac{100}{0.1}\right) = \frac{2.303}{k} \times 3 = 3 \times \frac{2.303 \times 0.3010}{k \times 0.3010} \approx 10 t_{1/2}.

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