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Coordination Compounds

JEE Main level, single correct, medium

1 of 4

Question 1 of 4

The magnetic moment of $[Fe(CN)_6]^{3-}$ complex ion according to spin-only formula is approximately:

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Answer: (D) $1.73\,\text{BM}$

Fe^{3+}

3d^5

. Since

CN^-

is strong field ligand, pairing occurs:

t_{2g}^5 e_g^0

, giving 1 unpaired electron (

n=1

\mu = \sqrt{1(1+2)} = \sqrt{3} \approx 1.73\,\text{BM}

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JEE Main Chemistry practice question on Coordination Compounds, with the answer and a step-by-step solution. Scan a question from your own book or paper to get a whiteboard video.

The magnetic moment of [Fe(CN)6]3−[Fe(CN)_6]^{3-}[Fe(CN)6​]3− complex ion according to spin-only formula is approximately:

JEE Main question paper PDF

More Chemistry practice

The magnetic moment of $[Fe(CN)_6]^{3-}$ complex ion according to spin-only formula is approximately: