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Integral Calculus

JEE Main level, numerical answer, medium

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Question 3 of 4

The value of the definite integral $\int_0^2 (3x^2 + 2x)\,dx$ is:

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Answer: 12

\int_0^2 (3x^2 + 2x)\,dx = [x^3 + x^2]_0^2 = (2^3 + 2^2) - 0 = 8 + 4 = 12

JEE Main question paper PDF

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JEE Main 2025 Apr 2 Shift 1 question paper

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JEE Main Mathematics practice question on Integral Calculus, with the answer and a step-by-step solution. Scan a question from your own book or paper to get a whiteboard video.

The value of the definite integral ∫02(3x2+2x) dx\int_0^2 (3x^2 + 2x)\,dx∫02​(3x2+2x)dx is:

JEE Main question paper PDF

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The value of the definite integral $\int_0^2 (3x^2 + 2x)\,dx$ is: