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Kinetic Theory

JEE Main level, single correct, medium

1 of 168

Question 1 of 168

The ratio of specific heats $\gamma = C_p/C_v$ for a rigid diatomic gas molecule is:

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Answer: (B) $7/5$

For a rigid diatomic gas, degrees of freedom

f = 5

. Thus

\gamma = 1 + \frac{2}{f} = 1 + \frac{2}{5} = \frac{7}{5}

JEE Main question paper PDF

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JEE Main 2025 Apr 2 Shift 1 question paper

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JEE Main Physics practice question on Kinetic Theory, with the answer and a step-by-step solution. Scan a question from your own book or paper to get a whiteboard video.

The ratio of specific heats γ=Cp/Cv\gamma = C_p/C_vγ=Cp​/Cv​ for a rigid diatomic gas molecule is:

JEE Main question paper PDF

More Physics practice

The ratio of specific heats $\gamma = C_p/C_v$ for a rigid diatomic gas molecule is: