Question 38 of 180

The charge on capacitor of capacitance $15\mu F$ in the figure given below is

A$60\mu C$B$130\mu C$C$260\mu C$D$585\mu C$

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Answer: (A) $60\mu C$

As we know, $Q=CV$
Here all capacitors are connected in series.
Thus, equivalent capacitance is ${C}_{eq}={\left(\dfrac{1}{10}+\dfrac{1}{15}+\dfrac{1}{20}\right)}^{-1}$ $={\left(\dfrac{6+4+3}{60}\right)}^{-1}=\dfrac{60}{13}\mu F$
Therefore, charge $Q=\dfrac{60}{13}\times 13=60\mu C$.
As the capacitors are connected in series, charge on each capacitor wil be same.

JEE Main Physics practice question on Capacitors (Grouping of capacitors), with the answer and a step-by-step solution. Scan a question from your own book or paper to get a whiteboard video.