Dual Nature of Matter

JEE Main level, single correct, medium

90 of 200

Question 90 of 200

K1K_1 and K2K_2 be the maximum kinetic energies of photoelectrons emitted from a surface of a given material for the light of wavelength λ1\lambda_1 and λ2\lambda_2, respectively. If λ1=2λ2\lambda_1=2\lambda_2 then the work function of material is given by:

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Answer: (D) K2−2K1K_2-2K_1

Using Einstein's photoelectric equation:

K1=hcλ1−ϕK_1 = \dfrac{hc}{\lambda_1} - \phi

K2=hcλ2−ϕK_2 = \dfrac{hc}{\lambda_2} - \phi

Given
λ1=2λ2\lambda_1 = 2\lambda_2, the first equation becomes:

K1=hc2λ2−ϕK_1 = \dfrac{hc}{2\lambda_2} - \phi

Multiplying by
22:

2K1=hcλ2−2ϕ2K_1 = \dfrac{hc}{\lambda_2} - 2\phi

Substituting
hcλ2=K2+ϕ\dfrac{hc}{\lambda_2} = K_2 + \phi from the second equation:

2K1=(K2+ϕ)−2ϕ2K_1 = (K_2 + \phi) - 2\phi

2K1=K2−ϕ2K_1 = K_2 - \phi

ϕ=K2−2K1\phi = K_2 - 2K_1

Answer:
K2−2K1K_2-2K_1

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